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THE CONSCIOUSNESS ATLAS
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ConsciousnessLearn · Explore · Joseph Anady

Factorizations controlling movement around the positive fixed point

The first difference shows whether an update raises or lowers the current state; the second shows whether it lies above or below one. For 1/5≤z<1, both expressions imply z<F(z)≤1. These sign relations support a monotone convergence argument within that invariant…

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eq-33dbe2f807166bmathematical expression
F(z)−z=(1−z)(2z+1)7z,  F(z)−1=(5z−1)(z−1)7z.F\left(z\right)-z=\frac{\left(1-z\right)\left(2z+1\right)}{7z},  F\left(z\right)-1=\frac{\left(5z-1\right)\left(z-1\right)}{7z}.

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The first difference shows whether an update raises or lowers the current state; the second shows whether it lies above or below one. For 1/5≤z<1, both expressions imply z<F(z)≤1. These sign relations support a monotone convergence argument within that invariant positive interval.

Terms & definitions

TermMeaning in this source
F

Average recurrence map

z

Current positive state

How it works

Read the definition from its right-hand expression to the quantity on the left. Its surrounding source records the intended input, state, or parameter context. Where the source leaves an operation unspecified, this page preserves that gap.

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Original context

Read the surrounding source passage
6.3 Proposition 3: every positive averaged trajectory converges to one

Two factorizations establish the result:

Fz−z=1−z2z+17z,  Fz−1=5z−1z−17z.

For z>1, these show 1<Fz<z. The sequence decreases while bounded below by one. For 1/5≤z<1, they show z<Fz≤1, so the sequence increases while bounded above by one. For 0<z<1/5, the next value is greater than one and thereafter belongs to the first case. A bounded monotone sequence has a limit; continuity and the positive fixed-point equation force that limit to be one.

For z0=2, local computation gives:

Iteration
Exact original notation
F\left(z\right)-z=\frac{\left(1-z\right)\left(2z+1\right)}{7z},  F\left(z\right)-1=\frac{\left(5z-1\right)\left(z-1\right)}{7z}.

Sources & provenance

01
Machine_Consciousness_Mathematical_Audit.docx
paragraph 169, math 1 · Sep 17, 2026
F\left(z\right)-z=\frac{\left(1-z\right)\left(2z+1\right)}{7z},  F\left(z\right)-1=\frac{\left(5z-1\right)\left(z-1\right)}{7z}.
02
Machine_Consciousness_Mathematical_Audit.docx
paragraph 169, math 1 · Sep 17, 2026
F\left(z\right)-z=\frac{\left(1-z\right)\left(2z+1\right)}{7z},  F\left(z\right)-1=\frac{\left(5z-1\right)\left(z-1\right)}{7z}.

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