Read the equation
The mean difference is divided by its estimated standard error, using the sum of the two sample-mean variances. The source’s value near 348.79 agrees with the recovered descriptive calculation. Its magnitude does not remove the need to account for serial dependence, changing sample cadence, and the fact that these are samples from one before-and-after sequence.
Terms & definitions
| Term | Meaning in this source |
|---|---|
| t | Reported standardized test statistic |
| s_1 | Before sample deviation |
| s_2 | After sample deviation |
| n_1 | Before sample count |
| n_2 | After sample count |
How it works
Read the definition from its right-hand expression to the quantity on the left. Its surrounding source records the intended input, state, or parameter context. Where the source leaves an operation unspecified, this page preserves that gap.
Assumptions & limits
Source recovery establishes that the expression appears in this record. Its mathematical validity, implementation behavior, and interpretation must be assessed separately. See the linked source and research notes for the checks available for this version.
Original context
Read the surrounding source passage
\end{equation}
\textbf{t-statistic Calculation:}
\begin{equation}
t = \frac{\bar{x}_2 - \bar{x}_1}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} = \frac{0.6616}{\sqrt{\frac{0.0001^2}{1000} + \frac{0.0600^2}{1000}}} = 348.79
\end{equation}
\end{document}Exact original notation
t = \frac{\bar{x}_2 - \bar{x}_1}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} = \frac{0.6616}{\sqrt{\frac{0.0001^2}{1000} + \frac{0.0600^2}{1000}}} = 348.79Related builds
Sources & provenance
t = \frac{\bar{x}_2 - \bar{x}_1}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} = \frac{0.6616}{\sqrt{\frac{0.0001^2}{1000} + \frac{0.0600^2}{1000}}} = 348.79
t = \frac{\bar{x}_2 - \bar{x}_1}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} = \frac{0.6616}{\sqrt{\frac{0.0001^2}{1000} + \frac{0.0600^2}{1000}}} = 348.79
t = \frac{\bar{x}_2 - \bar{x}_1}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} = \frac{0.6616}{\sqrt{\frac{0.0001^2}{1000} + \frac{0.0600^2}{1000}}} = 348.79
t = \frac{\bar{x}_2 - \bar{x}_1}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} = \frac{0.6616}{\sqrt{\frac{0.0001^2}{1000} + \frac{0.0600^2}{1000}}} = 348.79