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ConsciousnessLearn · Explore · Joseph Anady

Energy-state ODE: consumption and modulated input

The term −γC subtracts a contribution proportional to C, while I(t)[1+cos(φtFₙ)] injects a time-modulated input. The cosine multiplier lies between zero and two. For positive input it is nonnegative, but the net derivative can have either sign; nonnegative E is not…

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eq-a5f48deb750730mathematical expression
\frac{dE}{dt} = -\gamma C + I(t) \cdot \left(1 + \cos(\golden t \cdot \fib{n})\right)

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The term −γC subtracts a contribution proportional to C, while I(t)[1+cos(φtFₙ)] injects a time-modulated input. The cosine multiplier lies between zero and two. For positive input it is nonnegative, but the net derivative can have either sign; nonnegative E is not automatically enforced by the differential equation.

Terms & definitions

TermMeaning in this source
E

Energy-like state

γ

Consumption coefficient

C

Coupled state

I

External input function

F_n

Fibonacci integer

t

Time

How it works

Read the definition from its right-hand expression to the quantity on the left. Its surrounding source records the intended input, state, or parameter context. Where the source leaves an operation unspecified, this page preserves that gap.

Assumptions & limits

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Original context

Read the surrounding source passage
\label{eq:dC}
\end{equation}

\begin{equation}
\frac{dE}{dt} = -\gamma C + I(t) \cdot \left(1 + \cos(\golden t \cdot \fib{n})\right)
\label{eq:dE}
\end{equation}

\begin{equation}
\frac{dL}{dt} = \delta(C - L) \cdot \frac{\fib{n}}{\fib{n} + \fib{n-1}}
\label{eq:dL}
\end{equation}
Exact original notation
\frac{dE}{dt} = -\gamma C + I(t) \cdot \left(1 + \cos(\golden t \cdot \fib{n})\right)

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Sources & provenance

01
manuscript.tex
line 215 · Sep 22, 2026
\frac{dE}{dt} = -\gamma C + I(t) \cdot \left(1 + \cos(\golden t \cdot \fib{n})\right)
02
manuscript.tex
lines 212–215
\frac{dE}{dt} = -\gamma C + I(t) \cdot \left(1 + \cos(\golden t \cdot \fib{n})\right)
03
manuscript.tex
lines 214–217 · Sep 22, 2026
\frac{dE}{dt} = -\gamma C + I(t) \cdot \left(1 + \cos(\golden t \cdot \fib{n})\right)
04
manuscript.tex
lines 212–215
\frac{dE}{dt} = -\gamma C + I(t) \cdot \left(1 + \cos(\golden t \cdot \fib{n})\right)

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