Read the equation
This block records the manuscript’s rounded means, standard deviations, and equal sample sizes. The before mean is near 0.25 and the after mean near 0.912. These numbers summarize recorded samples; they do not reconcile the mismatch between the proposed reciprocal-variance score and the low baseline.
Terms & definitions
| Term | Meaning in this source |
|---|---|
| x_bar_1 | Reported before mean |
| x_bar_2 | Reported after mean |
| s_1 | Reported before standard deviation |
| s_2 | Reported after standard deviation |
| n_1 | 1000 before samples |
| n_2 | 1000 after samples |
How it works
Read the definition from its right-hand expression to the quantity on the left. Its surrounding source records the intended input, state, or parameter context. Where the source leaves an operation unspecified, this page preserves that gap.
Assumptions & limits
Source recovery establishes that the expression appears in this record. Its mathematical validity, implementation behavior, and interpretation must be assessed separately. See the linked source and research notes for the checks available for this version.
Original context
Read the surrounding source passage
\end{equation}
where $s_p = \sqrt{\frac{(n_1-1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2}}$.
For our data:
\begin{align}
\bar{x}_1 &= 0.2499, \quad s_1 = 0.0001, \quad n_1 = 1000 \\
\bar{x}_2 &= 0.9115, \quad s_2 = 0.0600, \quad n_2 = 1000
\end{align}
\begin{equation}
s_p = \sqrt{\frac{999 \cdot 0.0001^2 + 999 \cdot 0.0600^2}{1998}} = 0.0300
\end{equation}
\begin{equation}
d = \frac{0.9115 - 0.2499}{0.0300} = 22.06Exact original notation
\bar{x}_1 &= 0.2499, \quad s_1 = 0.0001, \quad n_1 = 1000 \\
\bar{x}_2 &= 0.9115, \quad s_2 = 0.0600, \quad n_2 = 1000Related builds
Sources & provenance
\bar{x}_1 &= 0.2499, \quad s_1 = 0.0001, \quad n_1 = 1000 \\ \bar{x}_2 &= 0.9115, \quad s_2 = 0.0600, \quad n_2 = 1000
\bar{x}_1 &= 0.2499, \quad s_1 = 0.0001, \quad n_1 = 1000 \\ \bar{x}_2 &= 0.9115, \quad s_2 = 0.0600, \quad n_2 = 1000
\bar{x}_1 &= 0.2499, \quad s_1 = 0.0001, \quad n_1 = 1000 \\ \bar{x}_2 &= 0.9115, \quad s_2 = 0.0600, \quad n_2 = 1000
\bar{x}_1 &= 0.2499, \quad s_1 = 0.0001, \quad n_1 = 1000 \\ \bar{x}_2 &= 0.9115, \quad s_2 = 0.0600, \quad n_2 = 1000