Read the equation
Composition acts from right to left. The increment and decrement cancel, the identity operations preserve the current value, and f₅ then resets it to one; the following identity and reciprocal leave one unchanged. The final output is one for every ordinary finite real initial input, so the chain does not preserve a seven-stage diversity of values.
Terms & definitions
| Term | Meaning in this source |
|---|---|
| f_1_to_f_7 | The seven defined scalar operators |
| z | Initial scalar |
How it works
Read the definition from its right-hand expression to the quantity on the left. Its surrounding source records the intended input, state, or parameter context. Where the source leaves an operation unspecified, this page preserves that gap.
Assumptions & limits
Source recovery establishes that the expression appears in this record. Its mathematical validity, implementation behavior, and interpretation must be assessed separately. See the linked source and research notes for the checks available for this version.
Original context
Read the surrounding source passage
6.1 Proposition 1: the sequential loop is a constant map For every finite real initial value in the ordinary interpretation, f7∘f6∘f5∘f4∘f3∘f2∘f1z=1. Proof. Addition and subtraction cancel. The next two operators preserve the value. The fifth maps every finite real input to one. Division by one and the reciprocal of one both return one. Therefore the complete composition is constant. No asymptotic argument, critical circulation speed, or activation threshold is needed. Starting from two, the exact path is 2→3→2→2→2→1→1→1.
Exact original notation
\left({f}_{7}∘{f}_{6}∘{f}_{5}∘{f}_{4}∘{f}_{3}∘{f}_{2}∘{f}_{1}\right)\left(z\right)=1.Sources & provenance
\left({f}_{7}∘{f}_{6}∘{f}_{5}∘{f}_{4}∘{f}_{3}∘{f}_{2}∘{f}_{1}\right)\left(z\right)=1.
\left({f}_{7}∘{f}_{6}∘{f}_{5}∘{f}_{4}∘{f}_{3}∘{f}_{2}∘{f}_{1}\right)\left(z\right)=1.