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ConsciousnessLearn · Explore · Joseph Anady

Zero instantaneous rate of C

The derivative condition says C is momentarily not changing. A derivative of zero at one time is weaker than a constant equilibrium and much weaker than attraction to that equilibrium. For the manuscript’s time-dependent forcing, the condition must be checked across…

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eq-ca7fc65dfd2e61mathematical expression
dC/dt=0dC/dt = 0

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The derivative condition says C is momentarily not changing. A derivative of zero at one time is weaker than a constant equilibrium and much weaker than attraction to that equilibrium. For the manuscript’s time-dependent forcing, the condition must be checked across time before a constant steady state is asserted.

Terms & definitions

TermMeaning in this source
C

Dynamical state

t

Time

How it works

Read the definition from its right-hand expression to the quantity on the left. Its surrounding source records the intended input, state, or parameter context. Where the source leaves an operation unspecified, this page preserves that gap.

Assumptions & limits

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Original context

Read the surrounding source passage
\begin{proof}
The Fibonacci ratio $\fib{n}/\fib{n-1}$ converges to $\golden$ as $n \to \infty$. The modulation term $\sin(\golden t) \cdot \fib{n}/\fib{n-1}$ therefore oscillates with amplitude approaching $\golden$.

At equilibrium, $dC/dt = 0$, giving:
\begin{equation}
\alpha(E^* - C^*) + \beta \cdot L^* \cdot \sin(\golden t) \cdot \golden = 0
\end{equation}

Time-averaging eliminates the oscillatory term (since $\langle \sin(\golden t) \rangle = 0$), yielding $E^* = C^*$.

Similarly, $dE/dt = 0$ at equilibrium gives:
Exact original notation
dC/dt = 0

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Sources & provenance

01
manuscript.tex
line 273 · Sep 22, 2026
dC/dt = 0
02
manuscript.tex
line 271
dC/dt = 0
03
manuscript.tex
line 273 · Sep 22, 2026
dC/dt = 0
04
manuscript.tex
line 271
dC/dt = 0

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