Read the equation
At a nonzero fixed point, multiplying z=F(z) by 7z yields 2z²−z−1=0. Factoring gives (2z+1)(z−1)=0. This algebra identifies all finite real fixed points of the displayed recurrence.
Terms & definitions
| Term | Meaning in this source |
|---|---|
| z | Candidate fixed point |
How it works
Read the definition from its right-hand expression to the quantity on the left. Its surrounding source records the intended input, state, or parameter context. Where the source leaves an operation unspecified, this page preserves that gap.
Assumptions & limits
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Original context
Read the surrounding source passage
Averaging is an additional coupling rule. It is not implied by drawing seven operators around a center. It should not be called the unique consequence of the proposed geometry. The fixed-point equation is 7z=5z+1+1/z⇔2z2−z−1=0⇔2z+1z−1=0. Hence zfixed,1=1, zfixed,2=−12. The derivative is
Exact original notation
7z=5z+1+1/z⇔2{z}^{2}-z-1=0⇔\left(2z+1\right)\left(z-1\right)=0.Sources & provenance
7z=5z+1+1/z⇔2{z}^{2}-z-1=0⇔\left(2z+1\right)\left(z-1\right)=0.
7z=5z+1+1/z⇔2{z}^{2}-z-1=0⇔\left(2z+1\right)\left(z-1\right)=0.