Sodium inactivation recovery rate

Read the equation

The exponential α_h supplies the recovery contribution α_h(1−h). It decreases with increasing voltage in this convention. Its balance with β_h determines how much sodium-channel availability remains.

Terms & definitions

How it works

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Original context

    }

    // β_m(V) = 4*exp(-(V+65)/18)
    float beta_m(float V_) const {
        return 4.0f * std::exp(-(V_ + 65.0f) / 18.0f);
    }

    // α_h(V) = 0.07*exp(-(V+65)/20)
    float alpha_h(float V_) const {
        return 0.07f * std::exp(-(V_ + 65.0f) / 20.0f);
    }

    // β_h(V) = 1/(1+exp(-(V+35)/10))
    float beta_h(float V_) const {
        return 1.0f / (1.0f + std::exp(-(V_ + 35.0f) / 10.0f));
    }

    // α_n(V) = 0.01(V+55)/(1-exp(-(V+55)/10))

α_h(V) = 0.07*exp(-(V+65)/20)

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