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This relation defines Equilibrium occupation: b_n^eq in the source section “XII. KINETIC RATE EQUATIONS · Equilibrium occupation: b_n^eq”. It specifies the displayed relationship between the named quantities or parameters. Its interpretation depends on the source’s stated variables and conditions; this record does not assign an unprovided physical or cognitive meaning to them.
Terms & definitions
The recovered passage does not supply a separate symbol table. Read the source context for the notation used in this version; familiar letters may carry different meanings in other builds.
How it works
Read Equilibrium occupation: b_n^eq as the quantity being defined or updated by this relation.
Substitute the source-defined variables or recorded values and follow the displayed arithmetic and indexing exactly.
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Assumptions & limits
This source expression was recovered from the pinned code revision. Its presence does not establish that the associated program was built, run, or scientifically validated.
Original context
Read the surrounding source passage
if (m < CROSS_HELIX_BONDS) neighbors.push_back(n + 1);
if (m + 4 <= CROSS_HELIX_BONDS) neighbors.push_back(n + 4);
}
return neighbors;
}
// Equilibrium occupation: b_n^eq = k_f(n)/(k_f(n) + k_b(n))
double equilibrium_occupation(int n, double phi_t) const {
double kf = formation_rate(n, phi_t);
double kb = breaking_rate(n, phi_t);
return kf / (kf + kb);
}
// Relaxation times
double slow_relaxation_time() const {
// τ_slow = 1/(k_f^min + k_b^min) · [1 + 43·σ_eff]
double k_min = std::min(base_formation_rate(22), base_breaking_rate(22));Exact original notation
Equilibrium occupation: b_n^eq = k_f(n)/(k_f(n) + k_b(n))