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THE CONSCIOUSNESS ATLAS
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ConsciousnessLearn · Explore · Joseph Anady

func TestFillWithin(t *testing.T) · P(fill within 3)

This relation defines P(fill within 3) in the source section “func TestFillWithin(t *testing.T) · P(fill within 3)”. It specifies the displayed relationship between the named quantities or parameters. Its interpretation depends on the source’s stated variables and…

Implementation mathematicsSource recovered; runtime not executed
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gh-eq-bb7bec2e56188fe3source-comment-equation
P(fillwithin3)=1−0.753=1−0.421875=0.578125.P(fill within 3) = 1 - 0.75^3 = 1 - 0.421875 = 0.578125.

Read the equation

This relation defines P(fill within 3) in the source section “func TestFillWithin(t *testing.T) · P(fill within 3)”. It specifies the displayed relationship between the named quantities or parameters. Its interpretation depends on the source’s stated variables and conditions; this record does not assign an unprovided physical or cognitive meaning to them.

Terms & definitions

The recovered passage does not supply a separate symbol table. Read the source context for the notation used in this version; familiar letters may carry different meanings in other builds.

How it works

  1. Read P(fill within 3) as the quantity being defined or updated by this relation.

  2. Substitute the source-defined variables or recorded values and follow the displayed arithmetic and indexing exactly.

  3. Use this version’s variable definitions and update order. The same symbol may be assigned a different meaning in another build.

Assumptions & limits

  • This source expression was recovered from the pinned code revision. Its presence does not establish that the associated program was built, run, or scientifically validated.

Original context

Read the surrounding source passage
func TestFillWithin(t *testing.T) {
	hz := []float64{0.25, 0.25, 0.25}
	// P(fill within 1) = 1 - 0.75 = 0.25.
	if !approx(FillWithin(hz, 1), 0.25) {
		t.Fatalf("fill within 1 wrong: %v", FillWithin(hz, 1))
	}
	// P(fill within 3) = 1 - 0.75^3 = 1 - 0.421875 = 0.578125.
	if !approx(FillWithin(hz, 3), 0.578125) {
		t.Fatalf("fill within 3 wrong: %v", FillWithin(hz, 3))
	}
	// A horizon beyond the vector uses the full vector.
	if !approx(FillWithin(hz, 99), 0.578125) {
		t.Fatalf("fill within a large horizon must use the full vector, got %v", FillWithin(hz, 99))
	}
	// A zero horizon fills nothing.
	if FillWithin(hz, 0) != 0 {
		t.Fatalf("fill within 0 must be 0, got %v", FillWithin(hz, 0))
Exact original notation
P(fill within 3) = 1 - 0.75^3 = 1 - 0.421875 = 0.578125.

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