Janady13/School-Work / School Work/Turn Objects into Flexible Arrays/Unique.js

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Field	Recorded value
Source type	GitHub source
Original record	Janady13/School-Work / School Work/Turn Objects into Flexible Arrays/Unique.js
Date	Not specified in source
Repository	Janady13/School-Work
Revision	4a666c890caf7c43c47d0572dbcc287373c7a78e
Branch	main
Path or archive member	School Work/Turn Objects into Flexible Arrays/Unique.js
Original SHA-256	82ddc3dab0e3c71f86a5f3cf5b8361ee466cecefd2a5b135c06ff42e4e9fc2cc
Git blob SHA	83c73b4ce89fbed7aed3df142061bf0c0411df7c
Reading-copy SHA-256	82ddc3dab0e3c71f86a5f3cf5b8361ee466cecefd2a5b135c06ff42e4e9fc2cc

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const customerDishes = [
    "Chicken Wings",
    "Fish Sandwich",
    "Beef Stroganoff",
    "Grilled Cheese",
    "Blue Cheese Salad",
    "Chicken Wings",
    "Reuben Sandwich",
    "Grilled Cheese",
    "Fish Sandwich",
    "Chicken Pot Pie",
    "Fish Sandwich",
    "Beef Stroganoff"
  ];

  // a set forces uniqueness within its elements 


  new Set([1, 2, 3, 4, 5, 6, 7, 8, 0]).size

  //the size element doesn't allow repenting elements 

  new Set2([1,1,2,3,4,5]).size

  // it would throw out the repeating number

  new Set3 ([[1],[2],[3],[3],[3]])

  // But it will not throw out seperate arrays to get the values of a set we have to iterate over it. You can use a foorloop

  for (const num of numbers) {
    console.log(num)
  }
  //This is one way to keep arrays from repeating themselves and keep things from repeating.