ThatAIguyA world of ideas

THE CONSCIOUSNESS ATLAS
Read. Experiment. Follow the evidence.

ConsciousnessLearn · Explore · Joseph Anady
12 minute lessonReady to learn

Follow an update pipeline

Read products, sums, gates, and ordering as a sequence of operations.

Course lessons · 4 of 5
Your goal

Calculate a composed update and explain why operation order matters.

Useful background: Normalization changes comparisons

A pipeline has intermediate states

The G16 source combines family transformations, blending, stability gating, and normalization. These stages are separate functions with intermediate outputs. To understand the whole update, trace a small input through each stage and keep the intermediate values.

Composition is often order-sensitive. Scaling an input and then adding a bias generally differs from adding the bias first and then scaling. Matching family names across two source versions therefore does not establish that their trajectories are equal.

(g∘f)(x)=g(f(x))(g\circ f)(x)=g(f(x))

Products create gates; sums mix contributions

A product becomes zero if any factor is zero. In a teaching learning-drive expression, multiplying activation, plasticity, and confidence makes each factor a gate on the final magnitude. The source must still define the allowed range and meaning of each factor.

A weighted sum combines contributions, and weights summing to one form an average when the relevant conditions hold. Its result should be inspected before later clipping or normalization, because those stages can hide large intermediate values.

Compare two operation orders

1Define both operations

Let f(x) = x + 1 and g(x) = 2x. These simple teaching functions isolate the effect of order.

2Apply addition before scaling

Starting at x = 3 gives four, then eight.

g(f(3))=2(3+1)=8g(f(3))=2(3+1)=8
3Reverse the order

Scaling first gives six, then seven. The functions are the same; their composition differs.

f(g(3))=2⋅3+1=7f(g(3))=2\cdot3+1=7

Make the idea respond

This laboratory implements the weighted-sum part of a composed calculation. Keep the values fixed and change one weight to see its normalized contribution change. It does not automatically compose f(x) = x + 1 with g(x) = 2x or compute the three-factor learning-drive product; those operations are worked separately above.

Change one input at a time. Predict what should happen, then compare the computed result with your prediction.

Teaching model · computed in your browser

Build a weighted score

Change component values and weights. Watch normalization turn them into a single, explainable score.

S=∑i(wi∑jwj)viS=\sum_i\left(\frac{w_i}{\sum_j w_j}\right)v_i

vᵢ is a component value from 0 to 1; wᵢ is a nonnegative raw weight. Divide every weight by their positive total before combining the values. These illustrative values are not measurements from a live AI system.

Try this: double all three weights. The normalized weights and total score should stay the same. Then set all weights to zero.

Experiment controls

Component A

Component B

Component C

The default worked example is shown below.

Raw weight sum6
Normalized weight sum1
Aggregate score0.6667Between 0.4 and 0.8
Each component’s contribution to the aggregateContribution on a common 0–1 scaleA0.4B0.2C0.066701
Each bar is the component value multiplied by its normalized weight. Add the contributions to get the score.

Normalize before adding: divide each raw weight by 6. Then S = 0.4 + 0.2 + 0.0667 = 0.6667. Multiplying every raw weight by the same positive factor leaves the result unchanged. Choosing weights expresses a modeling decision; it does not validate what a score means.

Every term in the weighted sum
ComponentValueRaw weightNormalized weightContribution
Component A0.830.50.4
Component B0.620.33330.2
Component C0.410.16670.0667
Open the full lab

Your turn.

Try an answer before opening a hint. Feedback will explain the result, and you can practice again.

Interactive practice is loading. The lesson, worked example, and printable questions remain available below.

View printable practice and solutions

Use these questions when studying without interactive controls. Opening a written solution does not earn progress.

  1. With f(x) = x + 1 and g(x) = 2x, what is g(f(4))?

    Read the solution

    The result is 2 × (4 + 1) = 10.

  2. A teaching drive is activation × plasticity × confidence = 0.8 × 0.5 × 0.25. What is the drive?

    Read the solution

    0.4 × 0.25 = 0.1.

  3. If one factor in that product is zero, what happens?

    • The result becomes undefined.
    • The product is zero.
    • The other factors are added instead.
    • The product becomes one.
    Read the solution

    Multiplying by zero gives zero for these finite factors.

  4. Two builds use the same family labels but apply gating and blending in different orders. What follows?

    • Their trajectories require comparison; equality is not established.
    • Their trajectories must be identical.
    • Both implementations must be invalid.
    • Their order can be ignored after naming the families.
    Read the solution

    Compare source-specific pipelines and outputs before claiming equivalence.

Follow the original record

Use the definitions you just practiced to read the project’s own notation, assumptions, and evidence.

The ideas to keep

  • Keep intermediate states visible.
  • Products can gate an update.
  • Compare operation order across revisions.

Reading completion is separate from your practice evidence.

Progress is kept in this browser. How learning works

Search equations, builds, manuscript text, and recovered sources.